If 500 BTUs are removed from 50 lb of water at 60°, what is the final water temperature?

To solve this question, we can use the specific heat formula, which helps us determine how a certain amount of heat affects the temperature of a substance. The specific heat capacity of water is approximately 1 BTU/lb/°F. This means that to raise or lower the temperature of one pound of water by one degree Fahrenheit, one BTU of heat must be added or removed.

In this scenario, we are removing 500 BTUs from 50 pounds of water at an initial temperature of 60°F. First, we need to calculate how much the temperature will drop when 500 BTUs are removed.

Using the heat transfer formula:

[

\text{Temperature change} = \frac{\text{Heat removed}}{\text{Mass} \times \text{Specific heat}}

]

Substituting in the values:

[

\text{Temperature change} = \frac{500 \text{ BTUs}}{50 \text{ lb} \times 1 \text{ BTU/lb/°F}} = \frac{500}{50} = 10°F

]

This indicates that the temperature of the water will drop by 10°F. Since the starting temperature is 60°F, we