If the resistance in an electric motor is cut in half, what will happen to the motor power, all else being equal?

When the resistance in an electric motor is cut in half, the relationship between current, voltage, and resistance, according to Ohm's Law (V = I * R), plays a crucial role in determining the effect on power. The power consumed by the motor can be defined using the formula P = I²R.

By halving the resistance, the current will increase because the same voltage is applied. Specifically, if resistance is reduced, the current will increase by a factor of two, since current (I) is inversely proportional to resistance (R) when voltage (V) is held constant. Thus, with a decrease in resistance, the new current can be calculated as twice the original current.

Power, which is related to the square of the current, will therefore increase. If the current doubles, the power will increase by a factor of four (since power is dependent on the square of the current, P = I²).

However, if considering just the direct impact of the decrease in resistance on the total power calculated directly from resistance and current, it can be interpreted that without specifying the fixed parameters or focusing on the operational context, one might consider the direct relationship of linear current contribution in a simplistic way which suggests doubling as appropriate